Если у вас возникли сложности с курсовой, контрольной, дипломной, рефератом, отчетом по практике, научно-исследовательской и любой другой работой - мы готовы помочь.
Предоплата всего
Подписываем
10 buyers came in a shop. What is the probability that 4 of them will do shopping if the probability to make purchase for each buyer is equal to 0,2? C (4, 10) * 0.2 ^ 4 * 0.8^6 = 0.088
145. A random variable X is distributed under an exponential law with parameter = 2. Find the mathematical expectation of X:
15 shots are made; 9 hits are registered. Find relative frequency of hits in a target. 9/15
150 shots have been made, and 25 hits have been registered. Find the relative frequency of hits in a target. 1/6
165. One letter has been randomly chosen from the word "PROBABILITY". What is the probability that the chosen letter is "I"? 2/11
196. For an event – appearance of four tails at tossing four coins - the opposite event is:4 heads
2 dice are tossed. Find probability that the same number of aces will appear on each of the dice: 1/6
3 dice are tossed. Find probability that each die lands on 5:1/216
4 independent trials are made, and in each of them an event A occurs with probability р. Probability that the event A will occur at least once is: 1 – q*(m);
5/6 – 3/6 = 2/6 = 1/3
A circle of radius 4 cm is placed in a big circle of radius 8 cm. Find the probability that a randomly thrown point in the big circle will get as well in the small circle. 16/64 = 1/4
A circle of radius l is placed in a big circle of radius L. Find probability that a randomly thrown point in the big circle will get as well in the small circle. l^2/L^2
A coin is tossed 5 times. Find probability that heads never will land: C(0.5)*0.5^5
A coin is tossed 5 times. Find probability that heads will land 3 times: C(3, 5) * 0.5 ^ 3 * 0.5 ^2
A coin is tossed 6 times. Find probability that “heads” will land 4 times. C(4,6)*0.5^4*0.5^2 = 15*0.5^6 = 15/64
A coin is tossed twice. Find probability that "heads" will land at least once.3/4
A coin is tossed twice. Find probability that "heads" will land in both times.1/4
A coming up seeds of wheat makes 90 %. Find probability that 4 of 6 sown seeds will come up: C(4,6) * 0.9^4 * 0.1 ^2
A coming up seeds of wheat makes 90 %. Find probability that only one of 6 sown seeds will come up: C(6, 6) * 0.9 ^6
A die is tossed before the first landing 3 aces. Find the probability that the first appearance of 3 will occur at the fourth tossing the die. 0,096
A discrete random variable X is given by the law of distribution: Then the probability р3 is equal to: 0.4
A discrete random variable X is given by the law of distribution: Then the probability р1 is equal to: 0.2
A pack of 52 cards is carefully shuffled. Find the probability that three randomly extracted cards will be kings: C(3,4)/ C(3, 52)
A point is put on an interval of length 2. Find probability that the distance from a point to the ends of the interval is more than 4/7.( 2 – 2*4/7)/2 = 3/7
A point is put on an interval of length 2. Find the probability that the distance from the point to the ends of the interval is more than 3/4. 2/8
A point is thrown on an interval of length 2. Find probability that the distance from a point to the ends of the interval is more than 5/6. (2 – 2*5/6)/2 = 1/6
A point is thrown on an interval of length 3. Find the probability that the distance from the point to the ends of the interval is more than 1. 1/3
A random event is: event is an event that can either take place, or not to take place for holding the set of conditions S.
A random variable X has normal density distribution . Find the value of parameter 2
A random variable X has normal density of distribution Find the value of parameк 4
A random variable X is distributed under an exponential law with parameter = 2. Find the dispersion of X: 1/4
A random variable X is distributed under Poisson law with parameter (Poisson distribution). Find M (X) =
A random variable X is distributed under the binomial law: Р (X=k) = (0 <p <1, q =1-p; k=1, 2, 3, …, n). Find M(X) = np
A random variable X is given by density of distribution of probabilities: , Find the function of distribution F(x). F(x) = x 0<x<1…..
A random variable X is given by the density of distribution of probabilities:
A random variable X is given by the integral function of distribution:
A random variable X is normally distributed with the parameters a and if its density is:
A reliable event is: - event is an event that necessarily will happen if a certain set of conditions S holds
A student knows 17 of 25 questions of examination. Find the probability that he (or she) knows 3 randomly chosen questions. 17/25 * 16/24 * 15/23
A student knows 25 of 30 questions of the program. Find probability that the student knows offered by the examiner 3 questions. 25/30 * 24/29 * 23/28
A student knows 7 of 12 questions of examination. Find probability that he (or she) knows randomly chosen 3 questions.7/12*6/11*5/10 = 0.15(90)
An impossible event is: (null) event is an event that certainly will not happen if the set of conditions S holds.
An improper integral of density of distribution in limits from – till is equal to 1
An urn contains 3 yellow and 6 red balls. Two balls have been randomly extracted from the urn. What is the probability that these balls will be of different color: 3*6/C(2, 9)
At shooting by a gun the relative frequency of hit in a target is equal to 0,9. Find the number of misses if 300 shots have been made. 300*0.9 = 270
At shooting from a rifle the relative frequency of hit in a target appeared equal to 0,8. Find the number of hits if 200 shots have been made. 200*0.8
Calculate : 1001
Calculate : 210
Details are made at two factories, and the first of them delivers 70%, and the second - 30% of all consumed production. 90 of each hundred details of the first factory are standard on the average, and 80 – of the second factory. Find the probability that a randomly taken detail will be standard. 0.7 * 0.9 + 0.3*0.8 = 0.87
Dialing the phone number, the subscriber has forgotten one digit and has typed it at random. Find probability that the necessary digit has been typed: 1/10
Differential function f(x) of a continuous random variable X is determined by the equality:
Dispersion D(X) of a continuous random variable X is determined by the following equality
Dispersion of a constant C is D(C) = 0
Dispersion of a discrete random variable X is D(x) =
Distribution of a discrete random variable is given by the table Find mathematical expectation M(X). -4/3
Distribution of a discrete random variable X is given by the table Find dispersion D (X). M(x) = -4/3 M(x^2) = 5 D(x) = 5 – (4/3)^2 = 3, (2)
Distribution of probabilities of a continuous random variable X is exponential if it is described by the densi
Electric lamps are made at two factories, and the first of them delivers 60%, and the second – 40% of all consumed production. 80 of each hundred lamps of the first factory are standard on the average, and 60 – of the second factory. Find probability that a bought lamp will be standard.0.6*08 + 0.4*0.6 = 0.72
Events A1, A2, A3, A4, A5 are called independent in union if: Several events are independent in union (or just independent) if each two of them are independent and each event and all possible products of the rest events are independent.
Find dispersion D(X) of a random variable X, knowing the law of its distributionM(x) = 0.2 + 1 + 0.9 = 2.1 M(x^2) = 0.2 + 2 + 2.7 = 4.9 D(x) = 0.49
Find mean square deviation (X): M(x) = 0.1 D(x) = 6.69(X) = 2.5865
Find the density of distribution f(x). производная
Find the function of distribution F(x). первообразная
Find the probability of hit of the random variable X in the interval (3; 5):
Five events form a complete group if they are: Some events form a complete group if in result of a trial at least one of them will appear.
For an event – dropping two tails at tossing two coins – the opposite event is: 2 heads
For opposite events and one of the following equalities holds: 0 1
Function of distribution of a random variable X is given by the formula . Find density of distribution f(x).Тупо производная
Function of distribution of a random variable X is: F(x) = P(X < x),
Function of distribution of the exponential law has the following form:
How many 4-place numbers can be composed of digits 1, 3, 9, 5? 4^4
How many 6-place phone numbers are there if only the digits “1”, “3” or “5” are used on the first place? 3*10^5
How many 6-place telephone numbers are there if the digits “0” and “9” are not used on the first place? 8*10^5
How many various 7-place numbers are possible to make of digits 1, 2, 3, 4, 5, 6, 7 if digits are not repeated?7! = 5040
How many ways are there to choose 3 books from 6? C(3, 6)
How many ways is there to choose two employees on two various positions from 8 applicants?A(2 , 8)
Identical products of three factories are delivered in a shop. The 1-st factory delivers 60 %, the 2-nd and 3-rd factories deliver 20 % each. 70 % of the 1st factory has the first sort, 80% of both the 2nd and the 3rd factories have the first sort. One product is bought. Find probability that it has the first sort: 0.74
If A and B are independent events then for Р(АВ) one of the following equalities holds: P(AB) = P(A)*P(B)
If an event A can happen only provided that one of incompatible events В1, В2, В3 forming a complete group will occur, Р (А) is calculated by the following formula:
If an event A can happen only provided that one of incompatible events В1, В2, В3, В4 forming a complete group will occur, РА(В2) is calculated by the following formula:
If dispersion of a random variable D(X) = 5 then D(5X) is equal to 25*5 = 125
If events A and B are compatible then for Р(А + В) one of the following equalities holds: P(A+B) =P(A) + P(B) – P(AB)
If events A and B are incompatible then for Р(А+ В) one of the following equalities holds: P(A+B) =P(A)+P(B)
If F(x) is an integral function of distribution of probabilities of a random variable X then P(a < X < b) is equal
If incompatible events A, B and C form a complete group, and P(A) + P(B) = 0,6 then P(C) is equal to: 0.4
If the probability of a random event A is equal to P(A), the probability of the opposite event is equal: 1 - P(A),
If X is uniformly distributed over (0, 7), calculate the probability that X < 2: 2/7
If X is uniformly distributed over (0, 7), calculate the probability that X > 6: 1/7
In a batch of 200 details the checking department has found out 13 non-standard details. What is the relative frequency of occurrence of non-standard details equal to? 13/200 = 0.065
In a batch of 7 products 3 of them have the first sort, and 4 – the second sort. One takes randomly 2 products. Find probability that both of them will have the first sort: 3/ 7 * 2/6
In a batch of 7 products 3 of them have the first sort, and 4 – the second sort. One takes randomly 2 products. Find probability that they have the same sort: 3/7 * 2/6 + 4/7*3/6
It is known that 15 % of all radio lamps are non-standard. Find probability that among 5 randomly taken radio lamps appears no more than 1 non-standard. C(0, 5)*0.15^0 * 0.85^5 + C(1, 5)*0.15^1 * 0.85^4 = 0.8355
It is known that 25 % of all details are non-standard. 8 details have been randomly taken. Find the probability that there is no more than 2 non-standard detail of the taken.C(0, 8 ) * 0.25 ^8 + C(1, 8)*0.25^1*0.75^7 + C(2, 8)* 0.25 ^2* 0.75 ^6
It is known that M (X) = - 3 and M (Y) = 5. Find M (3X – 2Y). = 1
Let A and B be events connected with the same trial. Show the event that means simultaneous occurrence of A and В.P=AB
Let A and B be events connected with the same trial. Show the event that means occurrence of only one of events A and B. A*B s 4ertoi + *B
Let A and B be events connected with the same trial. Show the event that means an appearance of A and a non-appearance of В. P(ABс чертой)
Let A and B be opposite events. Find Р(В) if Р(А) = 3/5. 2/5
Let be a density of distribution of a continuous random variable X. Then function of distribution is:
Let D(X) = 5. Then D(4X) is equal to 80
Let D(X) = 5. Then D(X – 4) is equal to 5
Let M be the number of all outcomes, and S be the number of non-favorable to the event A outcomes (S < M). Then P(A) is equal to: (M-S)/M
Let M(X) = 5. Find M(4X). = 20
Let M(X) = 5. Find M(X – 4) = 1
Let n be the number of all outcomes, m be the number of the outcomes favorable to the event A. The classical formula of probability of the event A has the following form: P(A) = m/n
Let the random variable X be given by the law of distribution
Let А1, А2, А3 be events connected with the same trial. Let A be the event that means occurrence only one of events А1, А2 and А3. Express the event A by the events А1, А2 and А3.1*2*A3 + 1*A2*3+A1*2*3
Let А1, А2, А3 be events connected with the same trial. Let A be the event that means none of events А1, А2 and А3 have happened. Express the event A by the events А1, А2 and А3А3 vse A s 4ertami
Let А1, А2, А3 be events connected with the same trial. Let A be the event that means occurrence only two of events А1, А2 and А3. Express the event A by the events А1, А2 and А3.
M(x) = = 2
Mathematical expectation of a continuous random variable X of which possible values belong to an interval [a, b] is (a+b)/2
Mathematical expectation of a normally distributed random variable X is a = 4, and mean square deviation is =5. Write the density of distribution X.
Mathematical expectation of a random variable X uniformly distributed in an interval (0, 1) is equal to1/2
Mathematical expectations are given for independent random variables X and Y. Find 21.5
Mean square deviation of a random variable X is determined by the following formula
One chooses randomly one letter of the word "HUNGRY". What is the probability that this letter is "E"? 0
One die is tossed. Find the probability that the number of aces doesn’t exceed 3. 1/2
One letter has been randomly chosen from the word "STATISTICS". What is the probability that the chosen letter is "S"? 0.3
Probabilities of opposite events A and satisfy the following condition: P(A) + P() = 1
Probability not to pass exam for the first student is 0,2, for the second - 0,4, for the third - 0,3. What is the probability that only one of them will pass the exam? 0.8*0.4*0.3 + 0.2 * 0.6 *0.3 + 0.2 * 0.4 * 0.7 = 0.188
Random variables X and Y are independent. Find dispersion of the random variable if it is known that D(X) = 1, D(Y) = 2. 16*1 + 25*2 = 66
Random variables X and Y such that Y =4X – 2 and D(X) = 3 are given. Find D(Y). 48
Show a differential function of the law of uniform distribution of probabilities
Show mathematical expectation of a discrete random variable X:
Show one of true properties of mathematical expectation (C is a constant): C
Show the Bernoulli formula
Show the Chebyshev inequalityP(|X – a| > ) D(X)/ 2
Show the formula of dispersion
Show the formula of total probability:
Show the Markov inequality: P(X > A) M(X)/A
The device consists of two independently working elements of which probabilities of non-failure operation are equal 0,8 and 0,7 respectively. Find probability of non-failure operation of two elements. 0.8*0.7 = 0.56
The dispersion D(X) of a random variable X is equal to 1,96. Find (Х): 1.4
The events A and B are compatible, Р(А) = 0,4; and Р(В) = 0,3. Find Р(. = 0.6 + 0.7 - 0.42 = 0.88
The events A and B are independent, Р(А) = 0,4; Р(В) = 0,3. Find .0.6*0.3 = 0.18
The events A and B are independent, Р(А) = 0,6; Р(В) = 0,8. Find . 0.4 *0.8 = 0.32
The formula is Bayes’s formulas
The function of distribution of a random variable X is given by the formula:.
The law of distribution of a discrete random variable X is given, M (X) = 5. Find P2 = 0.5 X1 = 11
The law of distribution of a discrete random variable X is given. Find Y. Y = 0.1
The letters T, A, O, B are written on four cards. One mixes the cards and puts them randomly in a row. What is the probability that it is possible to read the word "BOAT"? ¼! = 0.0416
The number of allocations of n elements on m is equal to:
The number of combinations of n elements on m is equal to
The number of permutations of n elements is equal to: Pn = n!
The pack of 52 cards is carefully hashed. Find probability that a randomly extracted card will be an ace: 4/36
The pack of 52 cards is carefully hashed. Find probability that two randomly extracted cards will be aces: C(2 , 4) / C(2,52)
The probability of an arbitrary event A is the number: 0<=P(x)<=1
The probability of an arbitrary event cannot be: less than 0 or more than 1
The probability of delay for the train №1 is equal to 0,1, and for the train №2 – 0,2. Find probability that at least one train will be late. 1 – 0.9*0.8 = 0.28
The probability of delay for the train №1 is equal to 0,15, and for the train №2 – 0,25. Find the probability that both trains will be late. 0.15 * 0.25 = 0.0375
The probability of delay for the train №1 is equal to 0,15; and for the train №2 – 0,25. Find the probability that at least one train will be late. 1 – 0.85 * 0.25 = 0.7875
The probability of delay for the train №1 is equal to 0,3, and for the train №2 – 0,45. Find probability that both trains will be late.0.3 * 0.45 = 0.135
The probability of hit in 10 aces for a given shooter at one shot is 0,9. Find probability that for 10 independent shots the shooter will hit in 10 aces exactly 6 times. C(6, 10) * 0.9^6 * 0.1^4 = 0.0111
The probability of hit in 10 aces for a shooter at one shot is 0,8. Find the probability that for 15 independent shots the shooter will hit in 10 aces exactly 8 times. C(8, 10) * 0.8^8 * 0.2^2
The probability of impossible event is the number: 0
The probability of joint occurrence of two dependent events is equal: P(AB) = P(A) PA(B)
The probability of reliable event is the number: 1
The probability that a continuous random variable X will take on a value belonging to an interval (a, b) is equal to
The probability to fail exam for the first student is 0,3; for the second – 0,4; for the third – 0,2. What is the probability that only one of them will pass the exam? 0.7 * 0.4 * 0.2 + 0.3 * 0.6 * 0.2 + 0.3 * 0.4 * 0.8
The random variable X is given by an integral function of distribution: Find probability of hit of the random variable X in an interval (1; 1,5): = 1/8
The urn contains 4 white and 6 black balls. One extracts by one randomly two balls without replacement. What is the probability that both balls will be black: 6/10 * 5/9
The urn contains 4 white and 6 black spheres. Two balls are randomly extracted from the urn. What is the probability that these balls will be of different color: 4*6/C(2, 10)
There are 11 white and 2 black balls in an urn. Four balls are randomly extracted. What is the probability that all balls are white?(4,11)/C(4,13) = 0.46 or 11/13 * 10/12 * 9/11 * 8/10 = 0.46
There are 11 white, 9 black, 15 yellow and 20 red balls in a box. Find probability that a randomly taken ball is black. 9/55
There are 11 white, 9 black, 15 yellow and 25 red balls in a box. Find probability that a randomly taken ball is white. 11/60
There are 12 sportsmen in a group, and 8 of them are masters of sport. 6 sportsmen have been randomly selected. Find the probability that there are 2 masters of sport among the selected sportsmen. C(2, 8) * C(4, 12)/ C(2, 20)
There are 15 red and 10 yellow balls in an urn. 6 balls are randomly extracted from the urn.
There are 20 students in a group, and 8 of them are pupils with honor. One randomly selects 10 students. Find probability that there are 6 pupils with honor among the selected students. C(6, 8) * C(4 , 12) / C(10, 20) = 28 * 495/184756 = 0.075
There are 20 white, 25 black, 10 blue and 15 red balls in an urn. One ball is randomly extracted. Find probability that the extracted ball is white or black. 45/70 = 9/14
There are 2000 tickets in a lottery. 1000 of them are winning, and the rest 1000 – non-winning. It was bought two tickets. What is the probability that both tickets are winning? 1000/2000 * 999/1999 = 0.24987
There are 23 white, 35 black, 27 yellow and 25 red balls in an urn. One ball has been extracted from the urn. Find the probability that the extracted ball is white or yellow. 27/110
There are 25 details in a box, and 20 of them are painted. One extracts randomly 4 details. Find probability that the extracted details are painted. 20/25 * 19/24 * 18/23 * 17/22 = 0.383
There are 4 children in a family. Assuming that the probabilities of births of boy and girl are equal, find the probability that the family has four boys: C(0, 4)*0.5^4
There are 4 detective lamps among 12 electric lamps. Find probability that randomly chosen 2 lamps will be defective. 4/12 * 3/11 = 0. (09)
There are 4000 tickets in a lottery, and 200 of them are winning. Two tickets have been bought. What is the probability that both tickets are winning? 200/4000 * 199/3999
There are 5 books on mathematics and 7 books on chemistry on a book shelf. One takes randomly 2 books. Find the probability that these books are on mathematics. 5/12 * 4/11 = 10/66
There are 5 books on mathematics and 8 books on biology in a book shelf. 3 books have been randomly taken. Find the probability that these books are on mathematics. 5/13 *4/12 *3 /11
There are 5 standard and 6 non-standard details in a box. One takes out randomly 2 details. Find probability that only one detail is standard. 5*6/C(2,11) = 30/55 = 6/11
There are 5 white and 4 black balls in an urn. One extracts randomly two balls. What is the probability that both balls are white?5/9*4/8 = 0.2(7)
There are 5 white and 7 black balls in an urn. One takes out randomly 2 balls. What is the probability that both balls are black?7/12 * 6/11 = 0.318
There are 6 children in a family. Assuming that probabilities of births of boy and girl are equal, find probability that the family has 4 boys: C(4,6)*0.5^4*0.5^2 = 15*0.5^6 = 15/64
There are 6 children in a family. Assuming that probabilities of birth of boy and girl are equal, find the probability that there are 4 girls and 2 boys in the family. C(4, 6) * 0.5 ^4 * 0.5^2 = 15/64
There are 6 white and 4 red balls in an urn. The event A consists in that the first taken out ball is white, and the event B – the second taken out ball is white. Find the probability = 6/10 * 5/9 = 1/3
There are 6 yellow and 6 red balls in an urn. 2 balls have been randomly taken. What is the probability that both balls are red? 6/12 * 5/11
There are 60 identical details in a box, and 8 of them are painted. One takes out randomly one detail. Find probability that a randomly taken detail will be painted: 8/60
There are 7 identical balls numbered by numbers 1, 2..., 7 in a box. All balls by one are randomly extracted from a box. Find probability that numbers of extracted balls will appear in ascending order. 1/7! = 1.98*10^4
There are 7 standard and 3 non-standard details in a box. 3 details have been randomly taken. Find the probability that only one of them is standard. C(1, 3) * C(2, 7)/ C(2, 10)
There are 7 yellow and 5 black balls in an urn. The event A consists in that the first randomly taken ball is black and the event B – the second randomly taken ball is yellow. Find P(AB). = 5/12 * 7/11
Three dice are tossed. Find probability that the sum of aces will be 6. 10/216
Three dice are tossed. Find the probability that the sum of aces will be 9. 1/9
Three shooters shoot in a target. The probability of hit in the target at one shot by the 1st shooter is 0,8; by the 2nd – 0,75 and by the 3rd – 0,7. Find the probability of hit by all the shooters. 0.8*0.75*0.7 = 0.42
Three shooters shoot on a target. Probability of hit in the target at one shot for the 1st shooter is 0,85; for the 2nd – 0,9 and for the 3rd – 0,95. Find probability of hit by all the shooters. 0.85*0.9*0.95 = 0,72675
Two dice are tossed. Find probability that the product of aces does not exceed 3. 5/36
Two dice are tossed. Find probability that the sum of aces does not exceed 2.1/36
Two dice are tossed. Find probability that the sum of aces doesn’t exceed 5. 10/36
Two dice are tossed. What is the probability that the sum of aces will be more than 8? 7/36
Two dice are tossed. What is the probability that the sum of aces will be more than 8?10/36
Two events form a complete group if they are: Some events form a complete group if in result of a trial at least one of them will appear.
Two independent events A and B are compatible, Р(А) = 0,6; and Р(В) = 0,75. Find = 0.4 + 0.25 – 0.4 * 0.25
Two shooters shoot in a target. The probability of hit by the first shooter is 0,85, and by the second – 0,9. Find the probability that only one of the shooters will hit in the target. 0.85*0.1 + 0.9 * 0.15 = 0.22
Two shooters shoot on a target. The probability of hit by the first shooter is 0,7, and the second – 0,8. Find probability that only one of shooters will hit in the target. 0.7*0.2 + 0.8*0.3 = 0.38
Two shooters shoot on a target. The probability of hit in the target by the first shooter is 0,8, by the second – 0,9. Find probability that only one of shooters will hit in the target: 0.8 * 0.1 + 0.9* 0.2
Two shots are made in a target by two shooters. The probability of hit by the first shooter is equal to 0,7, by the second – 0,8. Find probability of at least one hit in the target. 1 – 0.3*0.2 = 0.94
We say that a discrete random variable X is distributed under Poisson law with parameter (Poisson distribution) if P(X = k) =
We say that a discrete random variable X is distributed under the binomial law (binomial distribution) if Р (X = k) =
We say that a discrete random variable X is distributed under the geometric law (geometric distribution) if P(X=k) = P(X = m) = pqm–1
What is the probability that all these balls are red? C(6, 15)/ C(6, 25)
Which equality is true for dispersion of a random variable? C^2 * D(x)